What will be the output of the program?

```
public class SqrtExample
{
public static void main(String [] args)
{
double value = -9.0;
System.out.println( Math.sqrt(value));
}
}
```

Result: 12 questions

What will be the output of the program?

```
public class SqrtExample
{
public static void main(String [] args)
{
double value = -9.0;
System.out.println( Math.sqrt(value));
}
}
```

What will be the output of the program?

*System.out.println(Math.sqrt(-4D));*

Which header statement is missing in the given below program to get the desired output?

```
#include<stdio.h>
#include<math.h>
int main ()
{
double x = 1234321;
double result = sqrt(x);
printf("The square root of %.2lf is %.2lf\n", x, result);
return 0;
}
```

What will be the output of the program?

```
#include<stdio.h>
#include<math.h>
int main()
{
printf("%f\n", sqrt(36.0));
return 0;
}
```

What output will be produced by the code below?

```
import Foundation
let number = 16
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")
```

**Answer: **This code will not compile.

**Explanation:** The `sqrt()`

function can be called using two different types of parameter, neither of which are integers. In this example, Swift's type inference will consider `number`

to be an `Integer`

, which cannot be used by `sqrt()`

unless you typecast it.

What output will be produced by the code below?

```
import Foundation
let number = 16.0
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")
```

**Answer:**

Correct answer: "16.0 squared is 256.0, and its square root is 4.0".

**Explanation:** Using its type inference, Swift will consider `number`

to be an `Double`

, which will be interpolated correctly into the string even when `sqrt()`

is called. When `Doubles`

are interpolated into strings, they have .0 appended to their values when they have no fractional digits.

What output will be produced by the code below?

```
import Foundation
let number = 16.0
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")
```

**Answer:**

Correct answer: "16.0 squared is 256.0, and its square root is 4.0".

**Explanation:** Using its type inference, Swift will consider `number`

to be an `Double`

, which will be interpolated correctly into the string even when `sqrt()`

is called. When `Doubles`

are interpolated into strings, they have .0 appended to their values when they have no fractional digits.

What would be the output of the following code ?

`> sqrt(-17)`

`for(j=63 , i < 95 , i +=3) x += sqrt(j);`

What output will be produced by the code below?

```
import Foundation
let number = 16
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")
```

What output will be produced by the code below?

```
import Foundation
let number = 16.0
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")
```

Explain few useful functions in Excel.

Answer:

Following are the functions available in Excel for manipulating the data:

- Math and Financial Functions – SQRT, DEGREE, RAND(), GCD
- Logical Functions – IF, AND, FALSE, TRUE
- Date and Time functions – NOW(), DATEVALUE(), WEEKDAY(NOW())
- Index Match – VLOOKUP and INDEX MATCH
- Pivot tables

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