Question:

What does this code output:

def f(x,l=[]):
    for i in range(x):
        l.append(i*i)
    print(l) 

f(2)
f(3,[3,2,1])
f(3)

Answer:

[0, 1]
[3, 2, 1, 0, 1, 4]
[0, 1, 0, 1, 4]


Keywords:

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