What output will be produced by the code below?

import Foundation
let number = 16.0
print("\(number) squared is \(number * number), and its square root is \(sqrt(number))")



Correct answer: "16.0 squared is 256.0, and its square root is 4.0".

Explanation: Using its type inference, Swift will consider number to be an Double, which will be interpolated correctly into the string even when sqrt() is called. When Doubles are interpolated into strings, they have .0 appended to their values when they have no fractional digits.


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